Grind 75 Python 做題記錄 242. Valid Anagram
Grind 75 Python 做題記錄 242. Valid Anagram
class Solution:
def isAnagram(self, s: str, t: str) -> bool:
# 假如字串長度不同,回傳 False
if len(s) != len(t): return False
# 假如轉換成集合不同,回傳 False
s_set:set = set(s)
if s_set != set(t): return False
# 假如文字的數量不同,則回傳 False
for char in s_set:
if s.count(char) != t.count(char): return False
return True